# All Bank Written Questions Answer : AUST

All Bank Written Questions Answer দেয়ার উদ্দেশ্য একটাই- আসছে ১৭ আগস্ট, ২০১৮ সকাল বিকাল মিলে অনুষ্ঠিত হতে যাচ্ছে ৩ ব্যাংক ও ৫ ব্যাংক Combined Written Exam. একটা নিবে Repeat Question এর আদিপিতা AUST আর একটা নিবে Arts Faculty. তাই Bank Written Questions Answer সঠিক হওয়া চাই।

এই পোস্টে AUST কর্তৃক নেয়া All Bank Written Questions Answer (যেগুলো পাওয়া গেছে) হিসেবে রিটেনের ম্যাথ সল্যুশনসহ দেয়া হল।

## All Bank Written Questions Answer: By AUST

3 bank combined senior officer written question 2018 : AUST

Combined 3 Bank Senior Officer Question 2018: AUST

5 Bank Combined Officer Preli Exam 2018: Solution: Arts Faculty

5 bank combined officer written question 2018 : Arts Faculty

### Sonali Bank (Assistant Engineer IT)-2016

1. A, B and C enter into partnership with investment in the ratio 5:7:8. If at the end of the year A’s share of profit is 42360, how much is the total profit?

Solution:

 Let,A’ investment is 5x tkB investment is 7x tkC investment is 8x tkTotal investment= 5x+7x+8x=20xtkSo,5x = 42360Or, x = 8472Now, total investment=20×8472= 169440 tkAnswer: 169440 tk

2. Two-third of the faculty members of a department are female. Twelve of the male teachers are unmarried, while 60% of them are married. The total number of faculty members in the department is:

Solution:

 Let, total members are xthen female members are 2x/3So, male members are = x – 2x/3 = x/3ATQ,12 teachers are unmarriedOr, (100-60)% =40% =12So, 100% = 12*100/40 = 30Again,x/3 = 30Or, x=90Now, total faculty members are 90Answer:90

3. A trader marked the price of the T.V. 30% above the cost price of the T.V. and gave the purchaser 10% discount on the marked price, thereby gaining Rs. 340. Find the cost price of the TV?

Solution:

 Let,cost price of tv is x tkThen, the market price = x + x×30/100 = 13x/10 tkAt 10% discount on market price,Selling price = 13x/10 – 13x×10/10×100 = 117x/100 tkProfit = 117x/100 – x = 17x/100 tkATQ,17x/100 = 340Or,x = 340×100/17Or, x = 2000So, the cost price of the TV is 2000 tkAnswer: 2000 tk

4. A circular wheel 28 inches in diameter rotates (moves) the same number of inches per second as a circular wheel 35 inches in diameter. If the smaller wheel makes x revolutions per second, how many revolutions per minute does the larger wheel make in terms of x ?

Solution:

 As we know,1 revolution of circle= Circumference of that circleAgain,Circumference of circle=2πrGiven that,Diameter = 28 inchesSo, radius, r= 28/2= 14 inchesNow, circumference = 28π inchesHence,x revolutions per sec = 28πx inchesThen in 60 sec 28πx × 60 inchesATQ,28πx × 60 = 35πn=> n = 48xThusa the required no of revolutions is 48xAnswer: 48x

## All Bank Written Questions Answer: PKB SEO- 2018

PKB Senior Executive Officer Question 2018: AUST দেখতে ক্লিক করুন।

1. In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. The duration of the flight is:

Solution:

 Let,The duration of the fight be=x hrsOriginal distance be=6i00 kmAccording to the question,Original speed-Reduced speed=200600/x-600/(x+1/2)=200Or, 600/x-1200/(2x+1)=200Or, 3/x-{6/(2x+1)}=1Or, (6x+3-6x)/{x(2x+1)}=1Or, 2x2+3x-2x-3=0Or, x(2x+3)-1(2x-3)=0Or, (2x+3)(x-1)=0Now,X-1=0Or, X=1And2x+3=0Or, X=-(3/2)[neglecting the negative value]Answer: 1 hour

2. A alone can reap a certain field in 15 days and B in 12 days. If A begins alone and after a certain interval B joins him, the field is reaped in 7.5 days. How long did A and B work together.

Solution:

 Let,‘x’ be the number of days that A and B worked togetherAndTotal work be 1 portionA’s 1 day’s work =1/15B’S 1 day’s work = 1/12According to the question,(7.5 -x)/1 + x(1/15 + 1/12) = 1Or, (7.5 -x)/1 + 9x/60 = 1Or, (30-4x+9x )/60=1Or, 30 + 5x = 60Or, x = 6Hence, A & B work together 6 daysAnswer:6 days

3. a, b, c, d, e are 5 consecutive numbers in increasing order, deleting one of them from the set decreased the sum of the remaining numbers by 20% of the sum of 5. Which one of the number is deleted from the set?

Solution:

 Since a, b, c, d, e are increasing order consecutive number,b = a + 1,c = a + 2,d = a + 3,e = a + 4The sum of five numbers = a + a + 1 + a + 2 + a + 3 + a + 4 = 5a + 10We are given that the sum decreased by 20% when one number was deletedNew sum = (5a + 10) – 20% of (5a + 10) = 4a + 8Then, 4a + 8 = 5a + 10 – Dropped numberDropped number = a + 2 = c

4. A tank can be filled by a tap in 20 minutes and by another tap in 60 minutes. Both the taps are kept open for 10 minutes and then the first tap is shut off. After this, the tank will be completely filled in what time?

Solution:

 Work done by both in 1 minute= (1/20 + 1/60) = 4/60=1/15Work done by both in 10 minute=10/15 =2/3 portionRemaining part=(1 – 2/3)= 1/3 portionNow, 1/60 part is filled in 1 minuteSo, 1/3 part will be filled in 20 minuteAnswer: 20 m in

5. Two persons are running in 3.6km/h and 7.2 km/h speed. A train passes them in 9 & 9.5 seconds. What is the length of the train and speed of the train?

Solution:

 Let,The speed of the train = x kmhKnow that,Distance = speed × timeATQ,(x-3.6)×9 = (x-7.2) × 9.5Or, 9x – 32.4 = 9.5x – 68.4Or, 0.5x = 36Or, x = 72 kmhHere, speed of the train = 72 kmhSo, distance covered = {(72-3.6) × 9 × (5/18)}=171 meter

## All Bank Written Questions Answer:

### Basic Bank (Assistant Manager)-2018

BASIC Bank Assistant Manager Question -2018: AUST প্রিলি Question দেখতে ক্লিক করুন।

1. If a person invest Tk. 4000 at x% and Tk. 5000 at y%, he will get total Tk. 320 as interest. On the other hand if he invests Tk. 5000 at x% and Tk. 4000 at y%, he will get total Tk. 310 as interest. Find the value of x and y.

Solution:

 ,ATQ,{4000x/100}+{5000y/100}=320Or, 4x + 5y = 32 ————-(i)Again,{5000x/100}+{4000y/100}= 310Or,5x + 4y = 31—————-(ii)From (i)×5 – (ii)×4,20x + 25y = 16020x + 16y = 124—————————–Or,9y = 36Or, y = 4From equation(I)4x + 5y = 32x = (32-5*4)/4 = 3Answer:(3,4)

2. Working together pipe P, Q and T can fill a tank in 5 hours. Working together P and Q can fill it in 7 hours. Find in how many hours T can fill it?

Solution:

 Part filled by P, Q and T in 1 hour = 1/5Part filled by P and Q in 1 hour = 1/7Part filled by T in 1 hour = 1/5 – 1/7 = 2/352/35 part is filled by T in 1 hourSo, Whole part is filled by T in 35/2=17.2 hrsAns: 17.5 hours

3. A box contains 5 green, 4 yellow and 3 white balls. Three balls are drawn at random. What is the probability that they are not of same colour?

Solution:

 Total balls = 5 + 4 + 3 = 12No of ways of drawing 3 marbles out of 12 = 12c3 = 220event of getting 3 marbles of same color = 5c3 + 4c3 + 3c3=10+4+1= 15probability of getting 3 marbles of same color =15/220 = 3/44the probability that not getting marbles of same colour=(1-3/44)=41/44Answer: 41/44

4. There was a shipment of cars. Out of which half was black in colour. Remaining cars were equally blue, white and red. 70% of black cars, 80% of blue cars, 30% of white cars, 40% of red cars were sold. What percentage of total cars were sold?

Solution:

 Let,The total car was xSo,Black was = x/2Remaining cars =(x-x/2)=x/2ATQ,Other cars are equal coloursSo,Blue, White, and Red arex/6,x/6,x/6 respectivelySold cars:Black cars=x/2 of 70%=7x/20Blue cars=x/6 of 80%=2x/15White cars=x/6 of 30%=x/20Red cars=x/6 of 40%=x/15Total sold=(7x/20)+(2x/15)+(x/20)+(x/15)=180x/300Required percentage=(180x × 100)/(300x)=60%Answer:60%

5. A train passes a man in 3 second, and another train from opposite direction pass the man 4 second, both train same length. How long time need to pass the train each other?

Solution:

 Let,Both train length be xSo,Total length of two train=(x+x)=2xSpeed Of First train = x/3Speed Of second train =x/4We know that,Time=Distance/speedOr, T = 2x/(x/3 + x/4)Or, T= 2x*12/7xOr, T=24/7Hence, 3.43 second need to pass each otherAnswer:3.43 seconds

6. A man works for certain hours. If his hourly payment increase by 20%, what percent of working hours he may reduce so that total income remain unchanged?

Solution:

 Suppose,hourly payment=100tkAfter increased 20% then new payment=(100+20)=120tkSo,TK 20 reduced from tk 120Tk 100::::::::::::::::::::::={20*100/120}={100/6}=16.67%Answer:16.67%

7. There were some books of novel and non-fiction. Board discuss 3 times for any novel and 5 times for any non-fiction. During a year they discuss total 52 times. If there were 12 books, how many of them were novel?

Solution:

 Let,Novel books be xNon Fiction books be(12-x)According to the question,3x+5(12-x)=52Or,3x+60-5x=52Or -2x=-8Or, x=4.So, Nobel books were 4Answer:4

## All Bank Written Questions Answer:

### Sonali Bank (Cash Officer)-2018

Sonali Bank Officer Cash Preli Question 2018: AUST দেখতে ক্লিক করুন।

1. A, B and C are partners. ‘A’ whose money has been in the business for 4 months claims 1/8 of the profits, ‘B’ whose money has been in the business for 6 months claims 1/3 of the profits. If ‘C’ had Tk. 1560 in the business for 8 months, how much money did A and B contribute to the business?

Solution:

 A’s share of profit = 1/8B’s share of profit = 1/3So, C’s share of profit = 1 – (1/8 + 1/3) = 13/24Ratio of profit of A, B and C = 1/8:1/3:13/24 = 3:8:13Let, A contributes Tk. x for 4 months and B contribute Tk. y for 6 months.Ratio of investments of A, B and C = 4x : 6y : (1560 × 8) = 4x : 6y : 12480Now,4x : 12480 = 3 : 13Or, 4x/12480 = 3/13Or, 52x = 12480 × 3Or, x = (12480 × 3) / 52Or, x = 720Again,6y : 12480 = 8 : 13Or, 6y/12480 = 8/13Or, 78y = 12480 × 8Or, y = (2480 × 8) / 78Or, y = 1280So, contribution of A and B is Tk. 720 and Tk. 1280 respectively.Ans: Tk. 720 and Tk. 1280

2. Machine A, working alone at its constant rate, produces x pounds of peanut butter in 12 minutes. Machine B, working alone at its constant rate, produces x pounds of peanut butter in 18 minutes. How many minutes will it take machines A and B, working simultaneously at their respective constant rate, to produce x pounds of peanut butter?

Solution:

 Machine A and B produce in 1 minute = (x/12 + x/18) = 5x/365x/36 pounds is produced by both machines in 1 minuteOr, 1 pounds is produced by both machines in 36/5x minuteOr,  x pounds is produced by both machines in (36/5x × x) = 7.2 minuteAns: 7.2 minutes

3. Two trains running at the rate of 75 km and 60 km an hour respectively on parallel rails in opposite directions, are observed to pass each other in 8 seconds and when they are running in the same direction at the same rates as before, a person sitting in the faster train observes that he passes the other in 31.5 seconds. Find the lengths of the trains.

Solution:

 Moving in opposite direction:Relative speed of two trains = (75 + 60) km/hr = 135 km/hr = (135 × 5/18) m/s = 75/2 m/sLength of the both trains = (75/2 × 8) meters = 300 metersWhen moving in the same direction,Relative speed of two trains = (75 – 60) km/hr = 15 km/hr = (15 × 5/18) m/s = 25/6 m/sSo, Length of the slower train = (25/6 × 31.5) meters = 131.25 metersThus, length of the faster train = 300 – 131.25 = 168.75 metersAns: 131.25 meters and 168.75 meters.

4. A gardener plants two rectangular gardens in separate regions on his property. The first garden has an area of 600 square feet and a length of 40 feet. If the second garden has a width twice that of the first garden, but only half of the area, what is the ratio of the perimeter of the first garden to that of the second garden?

Solution:

 Width of the first garden = 600/40 = 15 feet.ATQ,width of the second garden = 15 × 2 = 30 feetand, area of the second garden = ½ × 600 = 300 sq. feetSo, length of the second garden = 300/30 = 10 feetNow, Perimeter of the first garden : Perimeter of the second garden= 2(40+15) : 2(10+30)= 110 : 80= 11 : 8

5. In a certain class, 1/5 of the boys are shorter than the shortest girls in the class and 1/3 of the girls are taller than the tallest boy in the class. If there are 16 students in the class and no two people have the same height, what percent of the students are taller than the shortest girl and shorter than the tallest boy?

Solution:

 Total students = 161/5 implies that no. of boys must be a multiple of 5And1/3 implies that the no. of girls must be a multiple of 3.So, Boys = 10 and Girls = 6 which satisfy the no. of total students (10 + 6) = 16Shorter boys = (1/5 × 10) = 2 and shortest girl = 1Taller girls = (1/3 × 6) =2 and tallest boy = 1Taller than shortest girls and shorter than tallest boy = (16 – 2 – 2 – 1 – 1) = 10So, Required percentage = (10/16 × 100) = 62.5%Ans: 62.5%

All Bank Written Questions Answer এর ক্ষেত্রে বেশিরভা্গ ম্যাথের সল্যুশন নেয়া হয়েছে ইউসুফ আলী, ডিডি, বাংলাদেশ ব্যাংক এর কাছ থেকে। অশেষ কৃতজ্ঞতা তাঁর প্রতি।

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## All Bank Written Questions Answer:

1. Sonali Bank (Assistant Programmer)-2016

প্রশ্ন পাওয়া যায়নি। তাই Bank Written Questions Answer এ অ্যাড করা গেল না।

তবে Sonali Bank Assistant Programmer Question 2016:AUST প্রিলি Question দেখতে ক্লিক করুন।

2. Sonali Bank (Sub Assistant Engineer/Mechanical/Architect/Electrical)-2016

প্রশ্ন পাওয়া যায়নি। তাই Bank Written Questions Answer এ অ্যাড করা গেল না।

3. ICB Assistant Programmer-2017

প্রশ্ন পাওয়া যায়নি। তাই Bank Written Questions Answer এ অ্যাড করা গেল না।

তবে ICB Assistant Programmer Question 2017: AUST এর প্রিলি Question দেখতে ক্লিক করুন।

4. Bangladesh Bank Assistant Director (Statistics)-2017

প্রশ্নে জেনারেল ম্যাথ ছিল না। তাই Bank Written Questions Answer এ অ্যাড করা গেল না।

5. PKB EO (Cash)-2018

প্রশ্ন পাওয়া যায়নি।

আপনার টাইমলাইনে শেয়ার করতে ফেসবুক আইকনে ক্লিক করুনঃ
Updated: December 23, 2019 — 6:12 pm

1. 2. দাদা আপনার অ্যাপ লিংকটা দিবেন দয়া করে

3. 4. AUST এর সবগুলো রিটেন প্রশ্ন একসাথে পোস্ট করলে ভালো হয়,,ধন্যবাদ।

1. Plz aust ar written & solution

5. please post all written solution of Aust.

6. 7. Sonali Bank FF quota SO & Sonali Bank officer cash FF quota written question dile valo hoto.

8. Please post all written question of AUST

9. thanks a lot

10. ক্ষমা চেয়ে নিয়ে বলছি,PKB SEO এর 1 নাম্বার প্রশ্নের সমাধান নিয়ে আমার সন্দেহ আছে।দেখুন,প্রশ্নে কিন্তু ফ্লাইটের original/planned/shcheduled/পূর্ব নির্ধারিত duration চায়নি।এবং প্রশ্নের শেষে tense হিসেবে আছে,”the duration of the flight is” যার মানে হলো নতুন যে ডিউরেশন দাঁড়িয়েছে সেটা চেয়েছে।স্বাভাবিক বা usual duration ছিল 1 ঘন্টা।গতি কমে সময় বেড়ে যাওয়ায় এখন দাঁড়িয়েছে দেড় ঘন্টা।তাই উত্তর দেড় ঘন্টা হওয়ার কথা।