bank job question : bank job question for written math suggestion for AUST দিব বলে কথা দিয়েছিলাম। তবে bank job question হিসেবে যে math গুলো দিলাম তা অবশ্যই আপনারা হাতে-কলমে practice করবেন। এই bank job question written math suggestion দেয়ার মানে এই নয় যে, এখান থেকেই সব কমন পড়বে। আপনারা AUST এর গুলো তো করবেনই, সাথে এই bank job question for written math suggestion ও করবেন। ভাগ্যে থাকলে সনাতন দা’র আড্ডার এই bank job question for written math suggestion থেকে কমন পেয়েও যেতে পারেন। নিচে প্রথমে bank job question, পরে সমাধান দেয়া হল।

**bank job question : written math suggestion**

All AUST Genuine bank job question for written math দেখতে ক্লিক করুন: **All Bank Written Questions Answer : AUST**

আপনার যে কোন প্রয়োজনে, চাকরির সার্কুলার ও আপডেট, এক্সাম ডেট, আপনার কোন কিছু জানার থাকলে নির্দ্বিধায় যোগদান করুন একঝাঁক প্রাণোচ্ছল তরুণের ফেসবুক গ্রুপ: BCS Limelight এ।

**bank job question : written math suggestion**

**মোট ৪১ টি ম্যাথ ও সমাধান।**

**01. The average price of 10 books is tk. 12 while the average price of 8 of these books is tk. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?**

**02. The population of a city is 35000. On an increase of 6% in the number of** **men and an increase of 4% in the number of women, the population would become 36760. What was the number of women initially?**

**03. An ore contains 25% of an alloy that has 90% iron. Other than this, in the** **remaining 75% of the ore, there is no iron. How many kilograms of the ore are needed to obtain 60 kg of pure iron?**

**04. In an institute, 60% of the students are boys and the rest are girls. Further** **15% of the boys and 7.5% of the girls are getting a fee waiver. If the number of those getting a fee waiver is 90, find the total number of students getting 50% concessions if it is given that 50% of those not getting a fee waiver are eligible to get half fee concession?**

**05. The length, breadth and height of a room are in ratio 3:2:1. If breadth and height are halved while the length is doubled, then the total area of the four walls of the room will:**

bank job question for written math

**06. Every month a man consumes 25 kg rice and 9 kg wheat. The price of rice is 20% of the price of wheat and thus he spends total tk. 350 on the rice and wheat per month. If the price of wheat is increased by 20% then what is the percentage reduction of rice consumption for the same expenditure of tk. 350? Given that the price of rice and consumption of wheat is constant:**

**07. In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1600 employees, then the no. of female employees who are computer literate?**

**08. The price of a car depreciates in the first year by 25% in the second year by 20% in third year by 15% and so on. The final price of the car after 3 years, if the present cost of the car is tk. 10,00,000:**

**09.600 students took the test on Physics and chemistry. 35% students failed in Physics and 45% students failed in chemistry and 40% of those who passed in chemistry also passed in Physics, then how many students failed in both:**

**10. In a factory there are three types of machine M1, M2 and M3 which produces 25%, 35% and 40% of the total products respectively. M1, M2 and M3 produces 2%, 4% and 5% defective products, respectively. what is the percentage of non-defective products?**

bank job question for written math

**11. An empty fuel tank of a car was filled with A type petrol. When the tank was half-empty, it was filled with B type petrol. Again when the tank was half-empty, it was filled with A type petrol. When the tank was half-empty again, it was filled with B type petrol. What is the percentage of A type petrol at present in the tank?**

**12. A reduction of 10% in the price of cloth enables a man to buy 6 meters of cloth more for tk. 2160. Find the reduced price and also the original price of cloth per meter.**

**13. By selling a bicycle for tk. 2,850, a shopkeeper gains 14%. If the profit is reduced to 8%, then the selling price will be:**

**14. A person sold a horse at a gain of 15%. Had he bought it for 25% less and sold it for tk. 600 less, he would have made a profit of 32%. The cost price of the horse was:**

**15. A bicycle marked at tk. 2,000, is sold with two successive discount of 20% and 10%. An additional discount of 5% is offered for cash payment. The selling price of the bicycle at cash payment is:**

bank job question for written math

**16. A sells an article to B at gain of 25% B sells it to C at a gain of 20% and C sells it to D at a gain 10%. If D pays tk. 330 for it, how much did it cost to A?**

**17. A and B together can complete a work in 3 days. They start together but after 2 days, B left the work. If the work is completed after two more days, B alone could do the work in:**

**18. Working 5 hours a day, A can Complete a work in 8 days and working 6 hours a day, B can complete the same work in 10 days. Working 8 hours a day, they can jointly complete the work in:**

**19. A complete 7/10 of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many days A and B can complete entire work together?**

**20. A can complete a piece of work in 36 days, B in 54 days and C in 72 days. All the three began the work the work together but A left 8 days before the completion of the work and B 12 days before the completion of work. Only C worked up to the end. In how many days was the work completed?**

bank job question for written math

**21. A and B can compete a piece of work in 18 days. They worked together for 12 days and then A left. B alone finished the work in 15 days. If tk. 1500 be paid for the work then A’s share is:**

**22. A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?**

**23. A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in:**

**24. An alloy contains zinc, copper and tin in the ratio 2:3:1 and another contains copper, tin and lead in the ratio 5:4:3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:**

**25. An amount of tk. 680 was invested at 6% rate of interest and another sum of money was invested at 10% interest. If the average interest on the total at the end of the year was 7.5%, how much was invested at 10%?**

bank job question for written math

**26. A can contains a mixture of two liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many litres of liquid A was contained by the can initially?**

**27. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:**

**28. Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:**

**29. A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is**

**30. Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?**

bank job question for written math

**31. Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on tk. 4000 for 2 years at 10% per annum. The sum placed on simple interest is:**

**32. The ratio between the perimeter and the breadth of a rectangle is 5: 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?**

**33. The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot © 26.50 per metre is Rs. 5300, what is the length of the plot in metres?**

**34. A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paisa per sq. m, is:**

**35. A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is:**

bank job question for written math

**36. A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?**

**37. In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?**

**38. Two dice are tossed. The probability that the total score is a prime number is:**

**39. Divide tk. 6000 into two parts so that simple interest on the first part for 2 years at 6% p.a. may be equal to the simple interest on the second part for 3 years at 8% p.a.**

**40. The slant height of a right circular cone is 10 m and its height is 8 m. Find the area of its curved surface.**

**41. The curved surface area of a cylindrical pillar is 264 m ^{2} and its volume is 924 m^{3}. Find the ratio of its diameter to its height.**

২২ সেপ্টেম্বর, ২০১৮ তারিখে AUST কর্তৃক অনুষ্ঠিতব্য ৮ ব্যাংক কম্বাইন্ড সিনিয়র অফিসার written exam preparation এর জন্য সনাতন দা’র আড্ডায় পরীক্ষার পূর্ব পর্যন্ত থাকছে বিশেষ আয়োজন।

All AUST Genuine bank job question for written এর জন্য গুরুত্বপূর্ণ focus writing দেখতে ক্লিক করুন: **Dhaka Metro Rail Project : Focus Writing for Bank ও অন্যান্য**

**bank job question : written math solution**

**01. The average price of 10 books is tk. 12 while the average price of 8 of these books is tk. 11.75. Of the remaining two books, if the price of one book is 60% more than the price of the other, what is the price of each of these two books?**

**Solution: **

Total cost of 10 books = tk. 120.

Total cost of 8 books = tk. 94.

So, The cost of 2 books = tk. (94/8)×2 = tk 26.

Let,

the price of each book be x and y.

So, x + y = 26 —————- (1)

Given,

the price of 1 book is 60% more than the other price

(160/100)y +y=26

Or, y(160/100+1) = 26.

Or, y =(26×100)/260.

Or, y = 10.

From (1),

x + y = 26

Or, x + 10 = 26

Or, x = 16.

**02. The population of a city is 35000. On an increase of 6% in the number of** **men and an increase of 4% in the number of women, the population would become 36760. What was the number of women initially?**

**Solution: **

Let,

number of men in the population be x.

So, Number of women = (35000-x)

Increase in the number of men = 6% of x = 6x/100

Increase in the number of women = (3500-x)×(4/100)

Increase in whole population = 36760-35000 = 1760

Now,

6x/100 + [(35000-x)×4/100] = 1760

Or, [(6x-4x)+35000×4]/100 = 1760

Or, 2x+35000×4 = 1760×100

Or, 2x = 176000-35000×4

X = 18000

Number of men = 18000

Number of women = 35000-18000 = 17000.

**03. An ore contains 25% of an alloy that has 90% iron. Other than this, in the** **remaining 75% of the ore, there is no iron. How many kilograms of the ore are needed to obtain 60 kg of pure iron?**

**Solution: **

Let,

there is 100 kg of ore.

25% ore contains 90% off Iron

that means 25 kg contains 25×(90/100) = 22.5 kg Iron

22.5 kg Iron remains in 100 kg of ore

Then, 1 kg of iron remains in = 100/22.5 kg ore

Hence,

60 kg iron remains in = (100×60)/22.5 = 266.66 kg ore.

**04. In an institute, 60% of the students are boys and the rest are girls. Further** **15% of the boys and 7.5% of the girls are getting a fee waiver. If the number of those getting a fee waiver is 90, find the total number of students getting 50% concessions if it is given that 50% of those not getting a fee waiver are eligible to get half fee concession?**

**Solution: **

Let,

assume there are 100 students in the institute.

Then, number of boys = 60

And, number of girls = 40

Further, 15% of boys i.e. = (15×60)/100 = 9 boys get fee waiver

So, boys do not get fee waiver = (60-9) = 51

7.5 % of girls i.e. = (7.5×40)/100 = 3 girls get fee waiver

So, girls do not get fee waiver = (40-3) = 37

Total students get fee waiver = (9+3) = 12

But, here given, 90 students are getting fee waiver.

So we compare,

12 = 90

So, 1 = 90/12 = 7.5

50% concession = 50% of 51 boys = 25.5 boys and

50% of 37 girls = 18.5 girls

Total = (25.5+18.5) = 44 students.

Hence, required students = 44×7.5 = 330.

**05. The length, breadth and height of a room are in ratio 3:2:1. If breadth and height are halved while the length is doubled, then the total area of the four walls of the room will:**

**Solution: **

Let length, breadth and height of the room be 3, 2, 1 unit respectively.

Area of walls = 2(l+b)×h = 2(3+2)×1 = 10 sq. unit.

ATQ,

length, breadth and height of room will become 6, 1 and 1/2 respectively.

Now, area of walls = 2(6+1)×1/2 = 7 sq. unit.

% decrease in the area of walls = {(10-7)×100}/10 = 30%.

bank job question for written math

**06. Every month a man consumes 25 kg rice and 9 kg wheat. The price of rice is 20% of the price of wheat and thus he spends total tk. 350 on the rice and wheat per month. If the price of wheat is increased by 20% then what is the percentage reduction of rice consumption for the same expenditure of tk. 350? Given that the price of rice and consumption of wheat is constant:**

**Solution: **

Let,

the price of wheat is x per kg.

Then,

price of wheat will be 5x per kg.

Expenditure on rice = 25×x = 25x.

Expenditure of wheat = 9×5x = 45x.

Total cost,

25x + 45x = 350.

Or, 70x = 350.

Or, x = 5.

Hence,

price of Rice = tk. 5 per kg.

Price of wheat = 5x = 5×5 = 25 per kg.

After 20% increase, price of wheat = 25 × (120/100)** =** 30 per kg.

Let the new amount of rice is N kg, then

N×5 + 9×30 = 350.

Or, 5N = 350 – 270

Or, 5N = 80

Or, N = 16 kg.

% decrease in the amount of rice = [(25-16)×100]/25 = 36%.

**07. In an office in Singapore there are 60% female employees. 50 % of all the male employees are computer literate. If there are total 62% employees computer literate out of total 1600 employees, then the no. of female employees who are computer literate?**

**Solution: **

Total employees = 1600

Female employees, 60% of 1600 = (60 ×1600) /100 = 960.

Then male employees = (1600 – 960) = 640

Male computer literate = 50 % of 640 = 320

Total computer literate = 62 % of 1600 = (62 ×1600) /100 = 992

Thus, Female computer literate = 992 – 320 = 672.

**08. The price of a car depreciates in the first year by 25% in the second year by 20% in third year by 15% and so on. The final price of the car after 3 years, if the present cost of the car is tk. 10,00,000:**

**Solution: **

Let,

present cost of the car = 10,00,000 tk

After 25% depreciation,

cost of the car = 75% of 10,00,000 = 75× 10,00,000/100 = 7,50,000 tk

After 20% depreciation,

cost of the car = 80% of 3x/4 = 80 × 7,50,000/100 = 6,00,000 tk

After 15% depreciation,

cost of the car = 85% of 6,00,000 = 85 × 6,00,000/100 = 5,10,000 tk

**09.600 students took the test on Physics and chemistry. 35% students failed in Physics and 45% students failed in chemistry and 40% of those who passed in chemistry also passed in Physics, then how many students failed in both:**

Solution:

Now,

passed in Chemistry, 55% of 600 = (55 × 600) / 100 = 330

From question, 40% of those who passed in Chemistry (330 Students) also passed in physics = (40 × 330) / 100 = 132

So, 132 students passed in both.

Therefore % of students who passed in both = (132 × 100) / 600 = 22%

Passed in both subject = 22% of total students

% of students who passed in either Physics or Chemistry or both,

= (65 +55) -22 = 98%

Thus, percentage of students who failed in both subjects = (100 – 98) % = 2%

Number of students who failed = 2% of 600 = 12.

**10. In a factory there are three types of machine M1, M2 and M3 which produces 25%, 35% and 40% of the total products respectively. M1, M2 and M3 produces 2%, 4% and 5% defective products, respectively. what is the percentage of non-defective products?**

**Solution: **

Non-defective products M^{1} = 25 X 0.98 = 24.5%

Non-defective products M^{2} = 35 X 0.96 = 33.6%

Non-defective products M^{3}= 40 X 0.95 = 38%

**Percentage of non-defective products = 24.5 + 33.6 + 38 = 96.1%**

bank job question for written math

**11. An empty fuel tank of a car was filled with A type petrol. When the tank was half-empty, it was filled with B type petrol. Again when the tank was half-empty, it was filled with A type petrol. When the tank was half-empty again, it was filled with B type petrol. What is the percentage of A type petrol at present in the tank?**

**Solution:**

Let,

the capacity of the tank be 100 litres.

Initially: A type petrol = 100 litres.

After first operation:

A type petrol = [(100/2)] = 50 litres;

B type petrol = 50 litres.

After second operation:

A type petrol = [(50/2 + 50)] = 75 litres;

B type petrol = [(50/2)] = 25 litres.

After third operation:

A type petrol = [(75/2)] = 37.5 litres;

B type petrol = [(25/2 + 50)] = 62.5 litres.

Required percentage = (100-67.5)% = 37.5%.

**12. A reduction of 10% in the price of cloth enables a man to buy 6 meters of cloth more for tk. 2160. Find the reduced price and also the original price of cloth per meter.**

**Solution:**

Money spent originally = tk. 2160.

Less money to be spent for now for the same length of cloth,

= 10% of 2160 = tk. 216.

It means tk. 216 enables a man to buy 6 meters of cloth.

So, reduced price = 216/6 = tk. 36 per meter.

And the original price = (100 ×36)/90 = tk. 40 per meter.

**13. By selling a bicycle for tk. 2,850, a shopkeeper gains 14%. If the profit is reduced to 8%, then the selling price will be:**

**Solution: **

Let,

Cost Price was X.

So,

X + 14% of X = 2850

Or, X + 14X/100 = 2850

Or, X + 0.14X = 2850

Or, 1.14X = 2850

Or, X = 2500.

So, Cost Price = tk. 2500.

Now, Selling Price When profit remains at 8%,

= 2500 + 8% of 2500

= tk. 2700.

**14. A person sold a horse at a gain of 15%. Had he bought it for 25% less and sold it for tk. 600 less, he would have made a profit of 32%. The cost price of the horse was:**

**Solution: **

Let,

the original CP = tk. X.

Hence,

SP= X + 15% of X = 115X/100 = tk. 23X/20.

New, CP = X – 25% of X = 75X/100 = 3X/4.

New SP = 3X/4 + 32% of 3X/4 = tk. 99X/100.

ATQ,

(23x/20) – (99x/100) = 600

Or, (115x-99x)/100 = 600

Or, 16x = 600*100

Or, X = 600×100/16 = tk. 3750.

**15. A bicycle marked at tk. 2,000, is sold with two successive discount of 20% and 10%. An additional discount of 5% is offered for cash payment. The selling price of the bicycle at cash payment is:**

**Solution: **

Marked Price = 2000.

SP after first Discount of 20% = 2000 – 20% of 2000 = 1600.

SP after second Discount of 10% = 1600 – 10% of 1600 = 1440.

Now, the final selling price at cash = 1440 – 5% of 1440 = tk. 1368.

bank job question for written math

**16. A sells an article to B at gain of 25% B sells it to C at a gain of 20% and C sells it to D at a gain 10%. If D pays tk. 330 for it, how much did it cost to A?**

**Solution: **

Let,

Cost Price for A was 100.

Then CP for B = 100 + 25% of 100 = 125.

CP for C = 125 + 20% of 125 = 150.

CP for D = 150 + 10% of 150 = 165.

But, D pay tk. 330.

So,

165 = 330

1 = 330/165

100 = (330 × 100)/165 = 200.

Thus, CP for A = tk. 200.

**17. A and B together can complete a work in 3 days. They start together but after 2 days, B left the work. If the work is completed after two more days, B alone could do the work in:**

**Solution:**

(A+B)’s one day’s work = 1/3 part;

(A+B) works 2 days together = 2/3 part;

Remaining work = 1-(2/3) = 1/3 part;

1/3 part of work is completed by A in two days;

Hence, one day’s work of A = 1/6;

Then, one day’s work of B = 1/3-1/6=1/6;

So, B alone can complete the whole work in 6 days.

**18. Working 5 hours a day, A can Complete a work in 8 days and working 6 hours a day, B can complete the same work in 10 days. Working 8 hours a day, they can jointly complete the work in:**

**Solution:**

Working 5 hours a day, A can complete the work in 8 days i.e.

= 5×8 = 40 hours;

Working 6 hours a day, B can complete the work in 10 days i.e.

= 6×10 = 60 hours;

(A+B)’s 1 hour’s work,

= (1/40+1/60)

=(3+2)/120

= 5/120

= 1/24;

Hence, A and B can complete the work in 24 hours i.e. they require = (24/8) = 3 working days to complete the work.

**19. A complete 7/10 of a work in 15 days, then he completed the remaining work with the help of B in 4 days. In how many days A and B can complete entire work together?**

**Solution: **

7/10 part of work has been completed by A in 15 days.

Then,

Rest work = 1-(7/10) = 3/10 part.

Given,

That 3/10 part of the work is completed by A and B together in 4 days. Means,

(A+B) completed the 3/10 of work in 4 days.

So, (A+B)’s 1 day’s work = 3/(10×4) = 3/40;

Hence,

(A+B) can complete the work in 40/3 = 13(1/3) days.

**20. A can complete a piece of work in 36 days, B in 54 days and C in 72 days. All the three began the work the work together but A left 8 days before the completion of the work and B 12 days before the completion of work. Only C worked up to the end. In how many days was the work completed?**

**Solution: **

Let,

the work be completed in **x** days.

C work for x days

then A works for (x-8) days and

B works for (x-12) days.

ATQ,

[(x-8)/36 + (x-12)/54 + x/72] = 1

Or, [(6x-48+4x-48+3x)/216] = 1

Or, 13x-96 = 216

Or, 13x = 216+96 = 312

Or, x = 312/13 = 24 days.

bank job question for written math

**21. A and B can compete a piece of work in 18 days. They worked together for 12 days and then A left. B alone finished the work in 15 days. If tk. 1500 be paid for the work then A’s share is:**

**Solution: **

A and B can complete the work in 18 days,

work rate = 100/18 = 5.55% per day.

They together can complete the work in 12 days = 5.55 × 12 = 66.66%.

Now, A leaves and B takes another 15 days to complete the whole work.

Work rate of B = 33.33/15 = 2.22% per day.

B work for (12+15) = 27 days.

So, Work done by B in 27 days = 2.22×27 = 60%

And So 40% work is done by A.

So, there share should be 60% and 40% ratio.

A’s share = 40% of 1500 = tk. 600.

**22. A can do a piece of work in 4 hours; B and C together can do it in 3 hours, while A and C together can do it in 2 hours. How long will B alone take to do it?**

Solution:

A’s 1 hour’s work = ¼

(B+C)’s 1 hour’s work = 1/3

(A+ C)’s 1 hours work = ½

(A +B+C)’s 1 hours work = (1/4 + 1/3) = 7/12

B’s 1 hours work = (7/12 – 1/2) = 1/12

.: B alone will take 12 hours to do the work.

**23. A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B had to leave and A alone completed the remaining work. The whole work was completed in:**

Solution:

(A+B)’s 1 day’s work = (1/15 + 1/10) = 1/6

Work done by A and B in 2 days = (2 × 1/6) = 1/3

Remaining work = (1 – 1/3) = 2/3

Now,

1/15 work is done by A in 1 day.

So, 2/3 work will be done by A in (15 × 2/3) = 10 days.

Hence, the total time taken = (10 + 2) = 12 days.

**24. An alloy contains zinc, copper and tin in the ratio 2:3:1 and another contains copper, tin and lead in the ratio 5:4:3. If equal weights of both alloys are melted together to form a third alloy, then the weight of lead per kg in new alloy will be:**

**Solution: **

Ratio of Zinc, Copper and Tin is given as,

Z : C : T = 2 : 3 : 1.

Now, let the first alloy be 12 kg (taken as 4 kg Zinc, 6 kg Copper and 2 Kg Lead).

Weight of second alloy = 12 kg as, C : T : L = 5 : 4 : 3. (taken as 5 kg Copper, 4 kg Tin and 3 Kg Lead.)

Alloys are mixed together to form third alloy. Then the ratio of content in it,

Z : C : T : L = 4 : (6+5) : (2+4) : 3

Weight of third alloy = 12+12 = 24 Kg.

So, weight of the Lead = 3/24 = 1/8 kg.

**25. An amount of tk. 680 was invested at 6% rate of interest and another sum of money was invested at 10% interest. If the average interest on the total at the end of the year was 7.5%, how much was invested at 10%?**

Solution:

Let,

At 10% interest, x tk was invested.

ATQ,

(680×0.06 + 0.1x)/(680 + x) = 7.5/100

Or, (4008 + 0.1x)/(680 + x) = 7.5/100

Or, 4080 + 10x = 7.5x + 5100

Or, 2.5x = 1020

Or, x = 1020/2.5

Or, x = 408

bank job question for written math

**26. A can contains a mixture of two liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many litres of liquid A was contained by the can initially?**

Solution:

Let,

the Can initially contains 7x and 5x of mixtures A and B respectively.

Quantity of A in mixture left

= (7x – 7/12 × 9) litres = (7x – 21/4) litres

Quantity of B in mixture left

= (5x- 5/12 × 9) litres = (5x – 15/4) litres

ATQ,

(7x – 21/4) / {(5x – 15/4)+9} = 7/9

Or, (28x – 21) / (20x + 21) = 7/9

Or, 252x – 189 = 140x + 147

Or, 112x = 336

Or, x = 3

So, initially A contained = 7x = 7 × 3 = 21 litres

**27. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:**

Solution:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

So,

(27x + 17y)/(x+y) = 23

Or, 27x + 17y = 23x + 23y

Or, 4x = 6y

Or, x/y = 3/2

**28. Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:**

Solution:

Let,

the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed

= (46 – 36) km/hr

= (10 × 5/18) m/sec

= 25/9 m/sec

So,

2x/36 = 25/9

Or, 2x = 100

Or, x = 50

**29. A train travelling at 48 kmph completely crosses another train having half its length and travelling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. The length of the platform is**

Solution:

Let the length of the first train be x metres.

Then, the length of the second train is (x/2) **metres.**

Relative speed = (48 + 42) kmph = (90 × 5/18) m/sec = 25 m/sec.

So,

{x + (x/2)}/25 = 12

Or, 3x = 300

Or, x = 200.

.: Length of first train = 200 m.

Let,

the length of platform be y metres.

Speed of the first train = (48 × 5/18) m/sec = 40/3 m/sec

Now,

(200 + y) × 3/40 = 45

Or, 600 + 3y = 1800

Or, y = 400 m.

So,

The length of the platform is = 400 m

**30. Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?**

Solution:

Suppose they meet x hours after 7 a.m.

Distance covered by A in x hours = 20x km.

Distance covered by B in x hours = 25(x – 1) km.

So,

20x + 25(x – 1) = 110

Or, 45x = 135

Or, x = 3.

So, they meet at (7+3) = 10 a.m.

bank job question for written math

**31. Simple interest on a certain sum of money for 3 years at 8% per annum is half the compound interest on tk. 4000 for 2 years at 10% per annum. The sum placed on simple interest is:**

Solution:

Compound Interest

= {4000 × (1 + 10/100)^{2} – 4000}

= {4000 × (11/10)^{2} – 4000}

= {4000 × (11/10) × (11/10) – 4000}

= (4840 – 4000)

= 840

So,

Sum = (420 × 100)/(3×8)

= 1750

**32. The ratio between the perimeter and the breadth of a rectangle is 5: 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle?**

Solution:

2(l+b)/b = 5/1

Or, 2l + 2b = 5b

Or, 3b = 2l

Or, b = 2l/3

Then,

Area = 216 cm^{2}

Or, l×b = 216

Or, l × 2l/3 = 216

Or, l^{2} = 324

Or, l = 18 cm

**33. The length of a rectangular plot is 20 metres more than its breadth. If the ****cost of fencing the plot © 26.50 per metre is Rs. 5300, what is the length of the plot in metres?**

Solution:

Let,

breadth = x metres.

Then,

length = (x + 20) metres.

Perimeter = (5300/26.50) m = 200 m

Now,

2{(x+20) + x} = 200

Or, 2x + 20 = 100

Or, 2x = 80

Or, x = 40

Hence, length = x + 20 = 60 m.

**34. A tank is 25 m long, 12 m wide and 6 m deep. The cost of plastering its walls and bottom at 75 paisa per sq. m, is:**

Solution:

Area to be plastered

= {2(l+ b) × h} + (l×b)

= {(2(25 + 12) × 6] + (25 × 12)} m^{2}

= (444 + 300) m^{2}

= 744 m^{2}

So,

cost of plastering = (744 × 75/100) tk = 558 tk

**35. A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is:**

Solution: Let the speed of the stream x mph.

Then,

Speed downstream = (10 + x) mph,

Speed upstream = (10 – x) mph.

Now,

36/(10-x) – 36/(10+x) = 90/60

Or, 72x × 60 = 90 (100 – x^{2})

Or, x^{2} + 48x – 100 = 0

Or, (x+50)(x – 2) = 0

(x+50) = 0 is not acceptable.

So, x-2 = 0

Or, x= 2 mph

bank job question for written math

**36. A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?**

Solution:

Total number of balls = (2 + 3 + 2) = 7.

Let,

S be the sample space.

Then,

n(S) = Number of ways of drawing 2 balls out of 7

= ^{7}C_{2}

= 7!/(2!(7-2)!

= (7×6)/(2×1)

= 21

Let,

E = Event of drawing 2 balls, none of which is blue.

n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls.

= ^{5}C_{2}

= 5!/(2!(5-2)!

= (5×4)/(2×1)

= 10

So, P(E) = n(E)/n(S) = 10/21

**37. In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?**

Solution:

Total number of balls, n(S) = (8 + 7 + 6) = 21.

Let,

E = event that the ball drawn is neither red nor green

= event that the ball drawn is blue.

So, n(E) = 7.

So, P(E) = n(E)/n(S) = 7/21 = 1/3

**38. Two dice are tossed. The probability that the total score is a prime number is:**

Solution:

Clearly, (S) = (6 × 6) = 36.

Let E = Event that the sum is a prime number.

Then E = {(1,1), (1,2), (1,4), (1,6), (2, 1), (2, 3), (2. 5), (3, 2), (3, 4), (4,1), (4,3), (5,2), (5, 6), (6, 1), (6,5)}

So, n(E) = 15.

So, P(E) = n(E)/n(S) = 15/36 = 5/12

**39. Divide tk. 6000 into two parts so that simple interest on the first part for 2 years at 6% p.a. may be equal to the simple interest on the second part for 3 years at 8% p.a.**

**Solution: **

Let 1^{st} part is x and 2^{nd} part is (6000-x).

ATQ,

(X×2×6/100) = ((6000-x)×3×8)/100

Or, 12x = 144000- 24x

Or, 36x = 144000

Or, x = 144000/36 = tk. 4000.

1^{st} part = tk. 4000;

2^{nd} part = tk. 2000.

**40. The slant height of a right circular cone is 10 m and its height is 8 m. Find the area of its curved surface.**

Solution:

l = 10 m,

h = 8 m.

So, r= √(l^{2} – h^{2})

= √(10^{2} – 8^{2})

= √(100 – 64)

= √36

= 6 m.

So, Curved surface area = πrl = (π × 6 × 10) m^{2} = 60π m^{2}

**41. The curved surface area of a cylindrical pillar is 264 m ^{2} and its volume is 924 m^{3}. Find the ratio of its diameter to its height.**

Solution:

ATQ,

πr^{2}h/2πrh = 924/264

Or, r = (924/264) × 2 = 7 m

And,

Area

2πrh = 264

Or, h = (264 × 7/22 × ½ × 1/7) = 6 m

.: Required ratio = 2r : h = 14 : 6 = 7 : 3

ফেসবুক বাটনে ক্লিক করে bank job question for written math suggestion কে আপনার টাইমলাইনে শেয়ার করে রাখুন।কষ্ট করে খুজতে হবে না। Notification অন করে রাখুন। নতুন পোস্ট এমনিতেই আপনার কাছে পৌছে যাবে।

Thanks a lot

At 9 no question, it said that 600 students took the test on Physics and chemistry. that means P+C = 600, but while finding the value of passed student in chemistry, it is written 55% 0f 600 = 330 ! 600 is the total amount not dedicatedly chemistry students number.

ow sorry, got it … I misunderstood it

অসংখ্য ধন্যবাদ

dada apnar document 1 mash age ami pdf korte partam. kintu ekhon pdf link ta passi na. dada solution plz.

দাদা, ২১ নম্বর অংক টার এন্সার কি ৯০০ হবে না?

দয়া করে আরেকবার দেখবেন।

ঠিক আছে।

600 is the right answer

Thanks dada.

দাদা, ৯ নং অংকে বলা আছে ৪০% উভয় বিষয়ে পাশ করেছে। তাহলে আবার ২২% বের করলেন কেন?

শুধুমাত্র ফিজিক্সে পাশ করে (১০০-৪০-৩৫)= ২৫ জন

শুধু মাত্র কেমিস্ট্রিতে পাশ করে (১০০-৪০-৪৫)= ১৫ জন

উভয় বিষয়ে ফেল করে, (১০০-৪০-২৫-১৫)= ২০ জন

অতএব ৬০০ জন এর মধ্যে উভয় বিষয়ে ফেইল করে ৬০০*২০/১০০= ১২০ জন।

এইটা কি ভুল? নাকি আমার প্রশ্ন বুঝায় ভুল আছে?

40% of those who passed in chemistry also passed in Physics

এর মানে হচ্ছে কেমেস্ট্রি পাস করাদের ৪০% ফিজিক্স পাস করে